Выполните действия:
а) $4 * 7^3 - 5 * 3^3$;
б) $(6^2 - 5^2)^3$;
в) $7! : 40$;
г) $3! + 3^3$;
д) $5! - 5^2$.
$4 \overset{3}{*} \overset{1}{7^3} \overset{5}{-} 5 \overset{4}{*} \overset{2}{3^3} = 1237$
1) $7^3 = 343$
2) $3^3 = 27$
3) 4 * 343 = 1372
4) 5 * 27 = 135
5) 1372 − 135 = 1237
Вычисления:
1)
$\snippet{name: column_multiplication, x: 49, y: 343}$
3)
$\snippet{name: column_multiplication, x: 343, y: 4}$
4)
$\snippet{name: column_multiplication, x: 27, y: 5}$
5)
$\snippet{name: op_column, sign: '-', x: '1372', y: '135', z: '1237 '}$
$(\overset{1}{6^2} \overset{3}{-} \overset{2}{5^2}\overset{4}{)^3} = 1331$
1) $6^2 = 36$
2) $5^2 = 25$
3) 36 − 25 = 11
4) $11^3 = 1331$
Вычисления:
$\snippet{name: column_multiplication, x: 121, y: 11}$
$\overset{1}{7!} \overset{2}{:} 40 = 126$
1) $7! = 1 * 2 * 3 * 4 * 5 * 6 * 7 = 6 * 20 * 42 = 120 * 42 = 5040$
2) 5040 : 40 = 126
Вычисления:
1)
2)
$\snippet{name: long_division, x: 5040, y: 40}$
$\overset{1}{3!} \overset{3}{+} \overset{2}{3^3} = 33$
1) $3! = 1 * 2 * 3 = 6$
2) $3^3 = 27$
3) 6 + 27 = 33
$\overset{1}{5!} \overset{3}{-} \overset{2}{5^2} = 95$
1) $5! = 1 * 2 * 3 * 4 * 5 = 6 * 20 = 120$
2) $5^2 = 25$
3) 120 − 25 = 95
Пожауйста, оцените решение