Приведите по два молекулярных уравнения реакций для следующих ионных:
а) $3Ca^{2+} + 2PO^{3-}_{4} = Ca_{3}(PO_{4})_{2}$↓;
б) $Fe^{3+} + 3OH^{-} = Fe(OH)_{3}↓$;
в) $2H^{+} + S^{2-} = H_{2}S↑$;
г) $H_{2}SiO_{3} + 2OH^{-} = SiO^{2-}_{3} + 2H_{2}O$;
д) $Fe(OH)_{3} + 3H^{+} = Fe^{3+} + 3H_{2}O$.
а) $3Ca^{2+} + 2PO^{3-}_{4} = Ca_{3}(PO_{4})_{2}↓$
$3Ca(NO_{3})_{2} + 2Na_{3}PO_{4} = 6NaNO_{3} + Ca_{3}(PO_{4})_{2}↓ $
$3CaCl_{2} + 2K_{3}PO_{4} = 6KCl + Ca_{3}(PO_{4})_{2}↓ $
б) $Fe^{3+} + 3OH^{-} = Fe(OH)_{3}↓$;
$Fe_{2}(SO_{4})_{3} + 6NaOH = 3Na_{2}SO_{4} + 2Fe(OH)_{3}↓ $
$FeBr_{3} + 3LiOH = 3LiBr + Fe(OH)_{3}↓ $
в) $2H^{+} + S^{2-} = H_{2}S↑$;
$Na_{2}S + H_{2}SO_{4} = Na_{2}SO_{4} + H_{2}S↑ $
$BaS + 2HNO_{3} = Ba(NO_{3})_{2} + H_{2}S↑$
г) $H_{2}SiO_{3} + 2OH^{-} = SiO^{2-}_{3} + 2H_{2}O$;
$H_{2}SiO_{3} + 2NaOH = Na_{2}SiO_{3} + 2H_{2}O$
$H_{2}SiO_{3} + 2KOH = K_{2}SiO_{3} + 2H_{2}O$
д) $Fe(OH)_{3} + 3H^{+} = Fe^{3+} + 3H_{2}O$.
$2Fe(OH)_{3}+ 3H_{2}SO_{4} = Fe_{2}(SO_{4})_{3} + 6H_{2}O$
$Fe(OH)_{3} + 3HCl = FeCl_{3} + 3H_{2}O$
Пожауйста, оцените решение
