$x^2 + bx + 6 = 0$
$x_1x_2 = 6$
6 = 1 * 6
6 = 2 * 3
6 = −1 * (−6)
6 = −2 * (−3)
$x_1 + x_2 = -b$
$b = -(x_1 + x_2)$
$b_1 = -(x_1 + x_2) = -(1 + 6) = -7$
$b_2 = -(x_1 + x_2) = -(2 + 3) = -5$
$b_3 = -(x_1 + x_2) = -(-1 + (-6)) = -(-7) = 7$
$b_4 = -(x_1 + x_2) = -(-2 + (-3)) = -(-5) = 5$
Ответ: при b = −7; −5; 5; 7.

$x^2 + bx - 12 = 0$
$x_1x_2 = -12$
12 = 1 * (−12)
12 = 2 * (−6)
12 = 3 * (−4)
12 = 4 * (−3)
12 = 6 * (−2)
12 = −1 * 12
12 = −2 * 6
12 = −3 * 4
12 = −4 * 3
12 = −6 * 2
12 = −12 * 1
$x_1 + x_2 = -b$
$b = -(x_1 + x_2)$
$b_1 = -(x_1 + x_2) = -(1 + (-12)) = 11$
$b_2 = -(x_1 + x_2) = -(2 + (-6)) = 4$
$b_3 = -(x_1 + x_2) = -(3 + (-4)) = 1$
$b_4 = -(x_1 + x_2) = -(4 + (-3)) = -1$
$b_5 = -(x_1 + x_2) = -(6 + (-2)) = -4$
$b_6 = -(x_1 + x_2) = -(12 + (-1)) = -11$
Ответ: при b = −11; −4; −1; 1; 4; 11.