Применяя теорему, обратную теореме Виета, решите уравнение:
1) $x^2 - 5x + 4 = 0$;
2) $x^2 + 5x + 4 = 0$;
3) $x^2 - 4x - 5 = 0$;
4) $x^2 + 4x - 5 = 0$;
5) $x^2 - 9x + 20 = 0$;
6) $x^2 - x - 2 = 0$;
7) $x^2 + 2x - 8 = 0$;
8) $x^2 - 3x - 18 = 0$.
$x^2 - 5x + 4 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -(-5) &\\
x_1x_2 = 4 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = 5 &\\
x_1x_2 = 4 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = 1 &\\
x_2 = 4 &
\end{cases}
\end{equation*}$
Ответ: 1; 4.
$x^2 + 5x + 4 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -5 &\\
x_1x_2 = 4 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = -1 &\\
x_2 = -4 &
\end{cases}
\end{equation*}$
Ответ: −1; −4.
$x^2 - 4x - 5 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -(-4) &\\
x_1x_2 = -5 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = 4 &\\
x_1x_2 = -5 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = 5 &\\
x_2 = -1 &
\end{cases}
\end{equation*}$
Ответ: 5; −1.
$x^2 + 4x - 5 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -4 &\\
x_1x_2 = 5 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = -5 &\\
x_2 = 1 &
\end{cases}
\end{equation*}$
Ответ: −5; 1.
$x^2 - 9x + 20 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -(-9) &\\
x_1x_2 = 20 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = 9 &\\
x_1x_2 = 20 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = 4 &\\
x_2 = 5 &
\end{cases}
\end{equation*}$
Ответ: 4; 5.
$x^2 - x - 2 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -(-1) &\\
x_1x_2 = -2 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = 1 &\\
x_1x_2 = -2 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = -1 &\\
x_2 = 2 &
\end{cases}
\end{equation*}$
Ответ: −1; 2.
$x^2 + 2x - 8 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -2 &\\
x_1x_2 = -8 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = -4 &\\
x_2 = 2 &
\end{cases}
\end{equation*}$
Ответ: −4; 2.
$x^2 - 3x - 18 = 0$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -b &\\
x_1x_2 = c &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = -(-3) &\\
x_1x_2 = -18 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 + x_2 = 3 &\\
x_1x_2 = -18 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x_1 = -3 &\\
x_2 = 6 &
\end{cases}
\end{equation*}$
Ответ: −3; 6.
Пожауйста, оцените решение