Найдите частное:
1) $\frac{7}{a^2} : \frac{28}{a^8}$;
2) $\frac{b^9}{8} : \frac{b^3}{48}$;
3) $\frac{27}{m^6} : \frac{36}{m^7n^2}$;
4) $\frac{6x^{10}}{y^8} : (30x^5y^2)$;
5) $49m^4 : \frac{21m}{n^2}$;
6) $\frac{16x^3y^8}{33z^5} : (-\frac{10x^2}{55z^6})$.
$\frac{7}{a^2} : \frac{28}{a^8} = \frac{7}{a^2} * \frac{a^8}{28} = \frac{1}{1} * \frac{a^6}{4} = \frac{a^6}{4}$
$\frac{b^9}{8} : \frac{b^3}{48} = \frac{b^9}{8} * \frac{48}{b^3} = \frac{b^6}{1} * \frac{6}{1} = 6b^6$
$\frac{27}{m^6} : \frac{36}{m^7n^2} = \frac{27}{m^6} * \frac{m^7n^2}{36} = \frac{3}{1} * \frac{mn^2}{4} = \frac{3mn^2}{4}$
$\frac{6x^{10}}{y^8} : (30x^5y^2) = \frac{6x^{10}}{y^8} * \frac{1}{30x^5y^2} = \frac{x^{5}}{y^8} * \frac{1}{5y^2} = \frac{x^{5}}{5y^{10}}$
$49m^4 : \frac{21m}{n^2} = 49m^4 * \frac{n^2}{21m} = 7m^3 * \frac{n^2}{3} = \frac{7m^3n^2}{3}$
$\frac{16x^3y^8}{33z^5} : (-\frac{10x^2}{55z^6}) = \frac{16x^3y^8}{33z^5} * (-\frac{55z^6}{10x^2}) = \frac{8xy^8}{3} * (-\frac{5z}{5}) = \frac{8xy^8}{3} * (-\frac{z}{1}) = -\frac{8xy^8z}{3}$
Пожауйста, оцените решение