Приведите к общему знаменателю дроби:
1) $\frac{1}{3a}$ и $\frac{2}{3b}$;
2) $\frac{4m}{p^3q^2}$ и $\frac{3n}{p^2q^3}$;
3) $\frac{5}{m - n}$ и $\frac{6}{m + n}$;
4) $\frac{6x}{x - 2y}$ и $\frac{y}{x + y}$;
5) $\frac{y}{6y - 36}$ и $\frac{1}{y^2 - 6y}$;
6) $\frac{1}{a^2 - 1}$ и $\frac{1}{a^2 + a}$.
$\frac{1}{3a} = \frac{1 * b}{3a * b} = \frac{b}{3ab}$
$\frac{2}{3b} = \frac{2 * a}{3b * a} = \frac{2a}{3ab}$
$\frac{4m}{p^3q^2} = \frac{4m * q}{p^3q^2 * q} = \frac{4mq}{p^3q^3}$
$\frac{3n}{p^2q^3} = \frac{3n * p}{p^2q^3 * p} = \frac{3np}{p^3q^3}$
$\frac{5}{m - n} = \frac{5(m + n)}{(m - n)(m + n)} = \frac{5(m + n)}{m^2 - n^2}$
$\frac{6}{m + n} = \frac{6(m - n)}{(m + n)(m - n)} = \frac{6(m - n)}{m^2 - n^2}$
$\frac{6x}{x - 2y} = \frac{6x(x + y)}{(x - 2y)(x + y)}$
$\frac{y}{x + y} = \frac{y(x - 2y)}{(x - 2y)(x + y)}$
$\frac{y}{6y - 36} = \frac{y}{6(y - 6)} = \frac{y * y}{6(y - 6) * y} = \frac{y^2}{6y(y - 6)}$
$\frac{1}{y^2 - 6y} = \frac{1}{y(y - 6)} = \frac{1 * 6}{y(y - 6) * 6} = \frac{6}{6y(y - 6)}$
$\frac{1}{a^2 - 1} = \frac{1}{(a - 1)(a + 1)} = \frac{a}{a(a - 1)(a + 1)} = \frac{a}{a(a^2 - 1)}$
$\frac{1}{a^2 + a} = \frac{1}{a(a + 1)} = \frac{a - 1}{a(a + 1)(a - 1)} = \frac{a - 1}{a(a^2 - 1)}$
Пожауйста, оцените решение