$\sqrt{7} + 2\sqrt{5} < 2 + \sqrt{35}$
$(\sqrt{7} + 2\sqrt{5})^2 < (2 + \sqrt{35})^2$
$7 + 2\sqrt{35} + 4 * 5 < 4 + 4\sqrt{35} + 35$
$-12 < 2\sqrt{35}$
$-6 < 0 < \sqrt{35}$
Неравенство верно.

$4\sqrt{6} + 2 > 2\sqrt{3} + 4\sqrt{2}$
$(4\sqrt{6} + 2)^2 > (2\sqrt{3} + 4\sqrt{2})^2$
$16 * 6 + 16\sqrt{6} + 4 > 4 * 3 + 16\sqrt{16} + 16 * 2$
100 > 44
Неравенство верно.