$y = \frac{2x - 1}{x + 6}$
y(x + 6) = 2x − 1
yx − 2x = −6y − 1
x(y − 2) = −(6y + 1)
$x = \frac{6y + 1}{2 - y}$
при y = 5:
$x = \frac{6 * 5 + 1}{2 - 5} = -\frac{31}{3} = -10\frac{1}{3}$;
при y = −3:
$x = \frac{6 * (-3) + 1}{2 - (-3)} = \frac{-18 + 1}{2 + 3} = \frac{-17}{5} = -3\frac{2}{5}$;
при y = 0:
$x = \frac{6 * 0 + 1}{2 - 0} = \frac{1}{2}$;
при y = 2:
$x = \frac{6 * 2 + 1}{2 - 2} = \frac{13}{0} = ∅$.
Ответ: $-10\frac{1}{3}; -3\frac{2}{5}; \frac{1}{2}; ∅$.

$y = \frac{x^2 + x - 2}{x + 3}$
при y = −10:
$\frac{x^2 + x - 2}{x + 3} = -10$
$x^2 + x - 2 = -10(x + 3)$
$x^2 + x - 2 + 10(x + 3) = 0$
$x^2 + x - 2 + 10x + 30 = 0$
$x^2 + 11x + 28 = 0$
D = 121 − 4 * 28 = 9
$x = \frac{-11 ± 3}{2}$
$x_1 = \frac{-11 - 3}{2} = -7$
$x_2 = \frac{-11 + 3}{2} = -4$
при y = 0:
$\frac{x^2 + x - 2}{x + 3} = 0$
$x^2 + x - 2 = 0$
D = 1 + 8 = 9
$x = \frac{-1 ± 3}{2}$
$x_1 = \frac{-1 - 3}{2} = -2$
$x_2 = \frac{-1 + 3}{2} = 1$
при y = −5:
$\frac{x^2 + x - 2}{x + 3} = -5$
$x^2 + x - 2 = -5(x + 3)$
$x^2 + x - 2 + 5(x + 3) = 0$
$x^2 + x - 2 + 5x + 15 = 0$
$x^2 + 6x + 13 = 0$
D = 36 − 4 * 13 = 36 − 52 = −16 < 0
Данное выражение не имеет смысла.
Ответ: −7 и −4; −2 и 1; ∅.