Сократите дробь:
а) $\frac{a(x - 2y)}{b(2y - x)}$;
б) $\frac{5x(x - y)}{x^3(y - x)}$;
в) $\frac{3a - 36}{12b - ab}$;
г) $\frac{7b - 14b^2}{42b^2 - 21b}$;
д) $\frac{25 - a^2}{3a - 15}$;
е) $\frac{3 - 3x}{x^2 - 2x + 1}$;
ж) $\frac{8b^2 - 8a^2}{a^2 - 2ab + b^2}$;
з) $\frac{(b - 2)^3}{(2 - b)^2}$.
$\frac{a(x - 2y)}{b(2y - x)} = \frac{a(x - 2y)}{-b(x - 2y)} = -\frac{a}{b}$
$\frac{5x(x - y)}{x^3(y - x)} = \frac{5x(x - y)}{-x^3(x - y)} = -\frac{3}{b}$
$\frac{3a - 36}{12b - ab} = \frac{3(a - 12)}{b(12 - a)} = \frac{3(a - 12)}{-b(a - 12)} = -\frac{3}{b}$
$\frac{7b - 14b^2}{42b^2 - 21b} = \frac{7b(1 - 2b)}{21b(2b - 1)} = \frac{7b(1 - 2b)}{-21b(1 - 2b)} = -\frac{1}{3}$
$\frac{25 - a^2}{3a - 15} = \frac{(5 - a)(5 + a)}{3(a - 5)} = \frac{(5 - a)(5 + a)}{-3(5 - a)} = -\frac{5 + a}{3}$
$\frac{3 - 3x}{x^2 - 2x + 1} = \frac{3(1 - x)}{(x - 1)^2} = \frac{3}{1 - x}$
$\frac{8b^2 - 8a^2}{a^2 - 2ab + b^2} = \frac{8(b^2 - a^2)}{(a - b)^2} = \frac{8(b - a)(b + a)}{(b - a)^2} = \frac{8(b + a)}{b - a}$
$\frac{(b - 2)^3}{(2 - b)^2} = \frac{(b - 2)^3}{(b - 2)^2} = b - 2$
Пожауйста, оцените решение