Найдите корни уравнения:
а) $16 + x^2 = 0$;
б) $0,3x^2 = 0,027$;
в) $0,5x^2 = 30$;
г) $-5x^2 = \frac{1}{20}$;
д) $x^3 - 3x = 0$;
е) $x^3 - 11x = 0$.
$16 + x^2 = 0$
$x^2 = -16$
∅
$0,3x^2 = 0,027$
$x^2 = 0,027 : 0,3$
$x^2 = 0,09$
$x = ±\sqrt{0,09}$
x = ±0,3
$0,5x^2 = 30$
$x^2 = 30 : 0,5$
$x^2 = 60$
$x = ±\sqrt{60}$
$x = ±\sqrt{4 * 15}$
$x = ±2\sqrt{15}$
$-5x^2 = \frac{1}{20}$
$x^2 = \frac{1}{20} : (-5)$
$x = \sqrt{\frac{1}{20} * (-\frac{1}{5})}$
$x = \sqrt{-\frac{1}{100}}$
∅
$x^3 - 3x = 0$
$x(x^2 - 3) = 0$
x = 0
$x^2 - 3 = 0$
$x^2 = 3$
$x = ±\sqrt{3}$
$x = {0;±\sqrt{3}}$
$x^3 - 11x = 0$
$x(x^2 - 11) = 0$
x = 0
$x^2 - 11 = 0$
$x^2 = 11$
$x = ±\sqrt{11}$
$x = {0;±\sqrt{11}}$
Пожауйста, оцените решение