Упростите выражение:
а) $\frac{6x^2}{5y} : \frac{3x}{10y^3}$;
б) $\frac{8c}{21d^2} : \frac{6c^2}{7d}$;
в) $\frac{3ab}{4xy} : (-\frac{21a^2b}{10x^2y})$;
г) $-\frac{18a^2b^2}{5cd} : (-\frac{9ab^3}{5c^2d^4})$.
$\frac{6x^2}{5y} : \frac{3x}{10y^3} = \frac{6x^2}{5y} * \frac{10y^3}{3x} = \frac{2x}{1} * \frac{2y^2}{1} = 4xy^2$
$\frac{8c}{21d^2} : \frac{6c^2}{7d} = \frac{8c}{21d^2} * \frac{7d}{6c^2} = \frac{4}{3d} * \frac{1}{3c} = \frac{4}{9cd}$
$\frac{3ab}{4xy} : (-\frac{21a^2b}{10x^2y}) = \frac{3ab}{4xy} * (-\frac{10x^2y}{21a^2b}) = \frac{1}{2} * (-\frac{5x}{7a}) = -\frac{5x}{14a}$
$-\frac{18a^2b^2}{5cd} : (-\frac{9ab^3}{5c^2d^4}) = \frac{18a^2b^2}{5cd} * \frac{5c^2d^4}{9ab^3} = \frac{2a}{1} * \frac{cd^3}{b} = \frac{2acd^3}{b}$
Пожауйста, оцените решение
