Приведите дроби:
а) $\frac{5}{36}, \frac{2}{x^2}, \frac{11}{3x}, \frac{7}{9x^2}, \frac{1}{4x}$ к знаменателю $36x^2$;
б) $\frac{1}{20y}, \frac{5}{x^2}, \frac{7}{20}, \frac{11}{2x}, \frac{3}{5xy}$ к знаменателю $20x^2y$.
$\frac{36x^2}{36} = x^2$
$\frac{5}{36} = \frac{5 * x^2}{36 * x^2} = \frac{5x^2}{36x^2}$
$\frac{36x^2}{x^2} = 36$
$\frac{2}{x^2} = \frac{2 * 36}{x^2 * 36} = \frac{72}{36x^2}$
$\frac{36x^2}{3x} = 12x$
$\frac{11}{3x} = \frac{11 * 12x}{3x * 12x} = \frac{132x}{36x^2}$
$\frac{36x^2}{9x^2} = 4$
$\frac{7}{9x^2} = \frac{7 * 4}{9x^2 * 4} = \frac{28}{36x^2}$
$\frac{36x^2}{4x} = 9x$
$\frac{1}{4x} = \frac{1 * 9x}{4x * 9x} = \frac{9x}{36x^2}$
$\frac{20x^2y}{20y} = x^2$
$\frac{1}{20y} = \frac{1 * x^2}{20y * x^2} = \frac{x^2}{20x^2y}$
$\frac{20x^2y}{x^2} = 20y$
$\frac{5}{x^2} = \frac{5 * 20y}{x^2 * 20y} = \frac{100y}{20x^2y}$
$\frac{20x^2y}{20} = x^2y$
$\frac{7}{20} = \frac{7 * x^2y}{20 * x^2y} = \frac{7x^2y}{20x^2y}$
$\frac{20x^2y}{2x} = 10xy$
$\frac{11}{2x} = \frac{11 * 10xy}{2x * 10xy} = \frac{110xy}{20x^2y}$
$\frac{20x^2y}{5xy} = 4x$
$\frac{3}{5xy} = \frac{3 * 4x}{5xy * 4x} = \frac{12x}{20x^2y}$
Пожауйста, оцените решение
