Представьте многочлен в виде квадрата суммы:
а) $x^2 + 2xy + y^2$;
б) $a^2 + 4ab + 4b^2$;
в) $9m^2 + 6mn + n^2$;
г) $16p^2 + 40pq + 25q^2$;
д) $x^2 + 2x + 1$;
е) $9 + 6a + a^2$;
ж) $16 + 8p + p^2$;
з) $4m^2 + 9n^2 + 12mn$;
и) $x^4 + 2x^2y^3 + y^6$;
к) $a^6 + 2a^3b^3 + b^6$.
$x^2 + 2xy + y^2 = (x + y)^2$
$a^2 + 4ab + 4b^2 = a^2 + 2 * a * 2b + (2b)^2 = (a + 2b)^2$
$9m^2 + 6mn + n^2 = (3m)^2 + 2 * 3m * n + n^2 = (3m + n)^2$
$16p^2 + 40pq + 25q^2 = (4p)^2 + 2 * 4p * 5q + (5q)^2 = (4p + 5q)^2$
$x^2 + 2x + 1 = (x + 1)^2$
$9 + 6a + a^2 = 3^2 + 2 * 3 * a + a^2 = (3 + a)^2$
$16 + 8p + p^2 = 4^2 + 2 * 4 * p + p^2 = (4 + p)^2$
$4m^2 + 9n^2 + 12mn = 4m^2 + 12mn + 9n^2 = (2m)^2 + 2 * 2m * 3n + (3n)^2 = (2m + 3n)^2$
$x^4 + 2x^2y^3 + y^6 = (x^2)^2 + 2 * x^2 * y^3 + (y^3)^2 = (x^2 + y^3)^2$
$a^6 + 2a^3b^3 + b^6 = (a^3)^2 + 2 * a^3 * b^3 + (b^3)^2 = (a^3 + b^3)^2$
Пожауйста, оцените решение