Решите уравнение:
а) $9x^2 - 1 - (3x - 2)^2 = 0$;
б) $x + (5x + 2)^2 = 25(1 + x^2)$;
в) $(2x - 3)^2 - 2x(4 + 2x) = 11$;
г) (4x − 3)(3 + 4x) − 2x(8x − 1) = 0.
$9x^2 - 1 - (3x - 2)^2 = 0$
$9x^2 - 1 - (9x^2 - 12x + 4) = 0$
$9x^2 - 1 - 9x^2 + 12x - 4 = 0$
12x = 5
$x = \frac{5}{12}$
$x + (5x + 2)^2 = 25(1 + x^2)$
$x + 25x^2 + 20x + 4 = 25 + 25x^2$
21x = 25 − 4
21x = 21
x = 1
$(2x - 3)^2 - 2x(4 + 2x) = 11$
$4x^2 - 12x + 9 - 8x - 4x^2 = 11$
−20x = 11 − 9
−20x = 2
x = −0,1
(4x − 3)(3 + 4x) − 2x(8x − 1) = 0
(4x − 3)(4x + 3) − 2x(8x − 1) = 0
$16x^2 - 9 - 16x^2 + 2x = 0$
2x = 9
x = 4,5
Пожауйста, оцените решение
