Решите уравнение:
а) $(x - 6)^2 - x(x + 8) = 2$;
б) $9x(x + 6) - (3x + 1)^2 = 1$;
в) $x(x - 1) - (x - 5)^2 = 2$;
г) $16x(2 - x) + (4x - 5)^2 = 1$.
$(x - 6)^2 - x(x + 8) = 2$
$x^2 - 12x + 36 - x^2 - 8x = 2$
−20x = 2 − 36
−20x = −34
x = 1,7
$9x(x + 6) - (3x + 1)^2 = 1$
$9x^2 + 54x - (9x^2 + 6x + 1) = 1$
$9x^2 + 54x - 9x^2 - 6x - 1 = 1$
48x = 1 + 1
48x = 2
$x = \frac{1}{24}$
$x(x - 1) - (x - 5)^2 = 2$
$x^2 - x - (x^2 - 10x + 25) = 2$
$x^2 - x - x^2 + 10x - 25 = 2$
9x = 2 + 25
9x = 27
x = 3
$16x(2 - x) + (4x - 5)^2 = 1$
$32x - 16x^2 + 16x^2 - 40x + 25 = 1$
−8x = 1 − 25
−8x = −24
x = 3
Пожауйста, оцените решение
