Решите уравнение:
а) $12x^2 - (4x - 3)(3x + 1) = -2$;
б) (x + 1)(x + 2) − (x + 3)(x + 4) = 0;
в) $10x^2 - (2x - 3)(5x - 1) = 31$;
г) (x − 2)(x − 3) − (x + 2)(x − 5) = 0.
$12x^2 - (4x - 3)(3x + 1) = -2$
$12x^2 - (12x^2 - 9x + 4x - 3) = -2$
$12x^2 - 12x^2 + 9x - 4x + 3 = -2$
5x = −2 − 3
5x = −5
x = −1
(x + 1)(x + 2) − (x + 3)(x + 4) = 0
$(x^2 + x + 2x + 2) - (x^2 + 3x + 4x + 12) = 0$
$x^2 + x + 2x + 2 - x^2 - 3x - 4x - 12 = 0$
−4x − 10 = 0
−4x = 10
x = −2,5
$10x^2 - (2x - 3)(5x - 1) = 31$
$10x^2 - (10x^2 - 15x - 2x + 3) = 31$
$10x^2 - 10x^2 + 15x + 2x - 3 = 31$
17x = 31 + 3
17x = 34
x = 2
(x − 2)(x − 3) − (x + 2)(x − 5) = 0
$(x^2 - 2x - 3x + 6) - (x^2 + 2x - 5x - 10) = 0$
$x^2 - 5x + 6 - x^2 + 3x + 10 = 0$
−2x = −6 − 10
−2x = −16
x = 8
Пожауйста, оцените решение
