Решите уравнение:
а) $6x(x + 2) - 0,5(12x^2 - 7x) - 31 = 0$;
б) $2x^3 - x(x^2 - 6) - 3(2x - 1) - 30 = 0$;
в) 12x(x − 8) − 4x(3x − 5) = 10 − 26x;
г) $8(x^2 - 5) - 5x(x + 2) + 10(x + 4) = 0$.
$6x(x + 2) - 0,5(12x^2 - 7x) - 31 = 0$
$6x^2 + 12x - 6x^2 + 3,5x - 31 = 0$
15,5x = 31
x = 2
$2x^3 - x(x^2 - 6) - 3(2x - 1) - 30 = 0$
$2x^3 - x^3 + 6x - 6x + 3 - 30 = 0$
$x^3 - 27 = 0$
$x^3 = 27$
x = 3
12x(x − 8) − 4x(3x − 5) = 10 − 26x
$12x^2 - 96x - 12x^2 + 20x + 26x = 10$
−50x = 10
x = −0,2
$8(x^2 - 5) - 5x(x + 2) + 10(x + 4) = 0$
$8x^2 - 40 - 5x^2 - 10x + 10x + 40 = 0$
$3x^2 = 0$
x = 0
Пожауйста, оцените решение
