Найдите $p(y) = p_1(y) - p_2(y)$, если:
а) $p_1(y) = 2y^3 + 8y - 11; p_2(y) = 3y^3 - 6y + 3$;
б) $p_1(y) = 4y^4 + 4y^2 - 13; p_2(y) = 4y^4 - 4y^2 + 13$;
в) $p_1(y) = y^3 - y + 7; p_2(y) = y^3 + 5y + 11$;
г) $p_1(y) = 15 - 7y^2; p_2(y) = y^3 - y^2 - 15$.
$p_1(y) = 2y^3 + 8y - 11; p_2(y) = 3y^3 - 6y + 3$:
$p(y) = p_1(y) - p_2(y) = 2y^3 + 8y - 11 + 3y^3 - 6y + 3 = 5y^3 + 2y - 8$
$p_1(y) = 4y^4 + 4y^2 - 13; p_2(y) = 4y^4 - 4y^2 + 13$:
$p(y) = p_1(y) - p_2(y) = 4y^4 + 4y^2 - 13 + 4y^4 - 4y^2 + 13 = 8y^4$
$p_1(y) = y^3 - y + 7; p_2(y) = y^3 + 5y + 11$:
$p(y) = p_1(y) - p_2(y) = y^3 - y + 7 + y^3 + 5y + 11 = 2y^3 + 4y + 18$
$p_1(y) = 15 - 7y^2; p_2(y) = y^3 - y^2 - 15$:
$p(y) = p_1(y) - p_2(y) = 15 - 7y^2 + y^3 - y^2 - 15 = y^3 - 8y^2$
Пожауйста, оцените решение
