Найдите $p(a;b) = p_1(a;b) + p_2(a;b)$, если:
а)
$p_1(a;b) = a + 3b$;
$p_2(a;b) = 3a - 3b$;
б)
$p_1(a;b) = 8a^3 + 3a^2b - 5ab^2 + b^3$;
$p_2(a;b) = 18a^3 - 3a^2b - 5ab^2 + 2b^3$;
в)
$p_1(a;b) = a^2 - 5ab - 3b^2$;
$p_2(a;b) = a^2 + b^2$;
г)
$p_1(a;b) = 10a^4 - 7a^3b - a^2b^2 + 6$;
$p_2(a;b) = 17a^4 - 10a^3b + a^2b^2 + 3$.
$p_1(a;b) = a + 3b$;
$p_2(a;b) = 3a - 3b$:
$p(a;b) = p_1(a;b) + p_2(a;b) = a + 3b + 3a - 3b = 4a$
$p_1(a;b) = 8a^3 + 3a^2b - 5ab^2 + b^3$;
$p_2(a;b) = 18a^3 - 3a^2b - 5ab^2 + 2b^3$:
$p(a;b) = p_1(a;b) + p_2(a;b) = 8a^3 + 3a^2b - 5ab^2 + b^3 + 18a^3 - 3a^2b - 5ab^2 + 2b^3 = 26a^3 - 10ab^2 + 3b^3$
$p_1(a;b) = a^2 - 5ab - 3b^2$;
$p_2(a;b) = a^2 + b^2$:
$p(a;b) = p_1(a;b) + p_2(a;b) = a^2 - 5ab - 3b^2 + a^2 + b^2 = 2a^2 - 5ab - 2b^2$
$p_1(a;b) = 10a^4 - 7a^3b - a^2b^2 + 6$;
$p_2(a;b) = 17a^4 - 10a^3b + a^2b^2 + 3$:
$p(a;b) = p_1(a;b) + p_2(a;b) = 10a^4 - 7a^3b - a^2b^2 + 6 + 17a^4 - 10a^3b + a^2b^2 + 3 = 27a^4 - 17a^3b + 9$
Пожауйста, оцените решение