Найдите $p(x) = p_1(x) + p_2(x)$, если:
а) $p_1(x) = 2x^3 + 5; p_2(x) = 3x^3 + 7$;
б) $p_1(x) = 4x^5 + 2x + 1; p_2(x) = x^5 + x - 2$;
в) $p_1(x) = 6x^2 - 4; p_2(x) = 5x^2 - 10$;
г) $p_1(x) = x^{11} + x^6 - 3; p_2(x) = 2x^{11} + 3x^6 + 1$.
$p_1(x) = 2x^3 + 5; p_2(x) = 3x^3 + 7$:
$p(x) = p_1(x) + p_2(x) = 2x^3 + 5 + 3x^3 + 7 = 5x^3 + 12$
$p_1(x) = 4x^5 + 2x + 1; p_2(x) = x^5 + x - 2$:
$p(x) = p_1(x) + p_2(x) = 4x^5 + 2x + 1 + x^5 + x - 2 = 5x^5 + 3x - 1$
$p_1(x) = 6x^2 - 4; p_2(x) = 5x^2 - 10$:
$p(x) = p_1(x) + p_2(x) = 6x^2 - 4 + 5x^2 - 10 = 11x^2 - 14$
$p_1(x) = x^{11} + x^6 - 3; p_2(x) = 2x^{11} + 3x^6 + 1$:
$p(x) = p_1(x) + p_2(x) = x^{11} + x^6 - 3 + 2x^{11} + 3x^6 + 1 = 3x^{11} + 4x^6 - 2$
Пожауйста, оцените решение
