Найдите $p(a) = p_1(a) + p_2(a)$, если:
а) $p_1(a) = 2a + 5; p_2(a) = 3a - 7$;
б) $p_1(a) = 7 - 2a; p_2(a) = -1 - 5a$;
в) $p_1(a) = 3a - 4; p_2(a) = 11 - 3a$;
г) $p_1(a) = -4 - 3a; p_2(a) = 7 - 8a$.
$p_1(a) = 2a + 5; p_2(a) = 3a - 7$:
$p(a) = p_1(a) + p_2(a) = 2a + 5 + 3a - 7 = 5a - 2$
$p_1(a) = 7 - 2a; p_2(a) = -1 - 5a$:
$p(a) = p_1(a) + p_2(a) = 7 - 2a - 1 - 5a = -7a + 6$
$p_1(a) = 3a - 4; p_2(a) = 11 - 3a$:
$p(a) = p_1(a) + p_2(a) = 3a - 4 + 11 - 3a = 7$
$p_1(a) = -4 - 3a; p_2(a) = 7 - 8a$:
$p(a) = p_1(a) + p_2(a) = -4 - 3a + 7 - 8a = -11a + 3$
Пожауйста, оцените решение
