Вычислите:
а) $\frac{(0,3)^3 * (0,3)^{12}}{(0,3)^13}$;
б) $\frac{(\frac{7}{8})^{16} * \frac{7}{8}}{(\frac{7}{8})^{15}}$;
в) $\frac{(0,09)^5 * (0,09)^{4}}{(0,09)^7}$;
г) $\frac{(\frac{1}{3})^{3} * (\frac{1}{3})^2}{\frac{1}{3}}$.
$\frac{(0,3)^3 * (0,3)^{12}}{(0,3)^13} = \frac{(0,3)^{3 + 12}}{(0,3)^13} = \frac{(0,3)^{15}}{(0,3)^13} = (0,3)^{15 - 13} = (0,3)^{2} = 0,09$
$\frac{(\frac{7}{8})^{16} * \frac{7}{8}}{(\frac{7}{8})^{15}} = \frac{(\frac{7}{8})^{16 + 1}}{(\frac{7}{8})^{15}} = \frac{(\frac{7}{8})^{17}}{(\frac{7}{8})^{15}} = (\frac{7}{8})^{17 - 15} = (\frac{7}{8})^{2} = \frac{49}{64}$
$\frac{(0,09)^5 * (0,09)^{4}}{(0,09)^7} = \frac{(0,09)^{5 + 4}}{(0,09)^7} = \frac{(0,09)^{9}}{(0,09)^7} = \frac{(0,09)^{9 - 7}} = \frac{(0,09)^{2}} = 0,0081$
$\frac{(\frac{1}{3})^{3} * (\frac{1}{3})^2}{\frac{1}{3}} = \frac{(\frac{1}{3})^{3 + 2}}{\frac{1}{3}} = \frac{(\frac{1}{3})^{5}}{\frac{1}{3}} = \frac{(\frac{1}{3})^{5}}{\frac{1}{3}} = (\frac{1}{3})^{5 - 1} = (\frac{1}{3})^{4} = \frac{1}{81}$
Пожауйста, оцените решение