Решите систему уравнений:
а) $\begin{equation*}
\begin{cases}
\frac{y + 1}{3x - 4} = \frac{1}{2}, &\\
\frac{5x + y}{3x + 11} = 1; &
\end{cases}
\end{equation*}$
б) $\begin{equation*}
\begin{cases}
\frac{3x + 10}{y + 1} = \frac{1}{12}, &\\
\frac{5x + y}{9x + 2y} = \frac{4}{5}. &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
\frac{y + 1}{3x - 4} = \frac{1}{2} &\\
\frac{5x + y}{3x + 11} = 1 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
2y + 2 = 3x - 4 &\\
5x + y = 3x + 11 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
2y - 3x = -2 - 4 &\\
5x - 3x + y = 11 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
2y - 3x = -6 &\\
2x + y = 11 | * (-2) &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
2y - 3x = -6 &\\
-4x - 2y = -22 &
\end{cases}
\end{equation*}$
2y − 3x − 4x − 2y = −6 − 22
−7x = −28
x = −28 : (−7)
x = 4
2x + y = 11
y = 11 − 2x
y = 11 − 2 * 4
y = 11 − 8
y = 3
Ответ: (4;3)
$\begin{equation*}
\begin{cases}
\frac{3x + 10}{y + 1} = \frac{1}{12} &\\
\frac{5x + y}{9x + 2y} = \frac{4}{5} &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
12(3x + 10) = y + 1 &\\
5(5x + y) = 4(9x + 2y) &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
36x + 120 = y + 1 &\\
25x + 5y = 36x + 8y &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
36x - y = 1 - 120 &\\
25x - 36x + 5y - 8y = 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
36x - y = -119 | * (-3) &\\
-11x - 3y = 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
-108x + 3y = 357 &\\
-11x - 3y = 0 &
\end{cases}
\end{equation*}$
−108x + 3y − 11x − 3y = 357
−119x = 357
x = 357 : (−119)
x = −3
−11x − 3y = 0
−3y = 11x
−3y = 11 * (−3)
−3y = −33
y = −33 : (−3)
y = 11
Ответ: (−3;11)
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