Решите систему уравнений методом подстановки:
а) $\begin{equation*}
\begin{cases}
5x - 3y = 14, &\\
2x + y = 10; &
\end{cases}
\end{equation*}$
б) $\begin{equation*}
\begin{cases}
x + 5y = 35, &\\
3x + 2y = 27; &
\end{cases}
\end{equation*}$
в) $\begin{equation*}
\begin{cases}
7x - 2y = 15, &\\
2x + y = 9; &
\end{cases}
\end{equation*}$
г) $\begin{equation*}
\begin{cases}
x + 3y = 2, &\\
2x + 3y = 7. &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
5x - 3y = 14 &\\
2x + y = 10 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
5x - 3y = 14 &\\
y = 10 - 2x &
\end{cases}
\end{equation*}$
5x − 3 * (10 − 2x) = 14
5x − 30 + 6x = 14
11x = 14 + 30
11x = 44
x = 44 : 11
x = 4
y = 10 − 2x = 10 − 2 * 4 = 10 − 8 = 2
Ответ: (4;2)
$\begin{equation*}
\begin{cases}
x + 5y = 35 &\\
3x + 2y = 27 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 35 - 5y &\\
3x + 2y = 27 &
\end{cases}
\end{equation*}$
3 * (35 − 5y) + 2y = 27
105 − 15y + 2y = 27
−13y = 27 − 105
−13y = −78
y = −78 : (−13)
y = 6
x = 35 − 5y = 35 − 5 * 6 = 35 − 30 = 5
Ответ: (5;6)
$\begin{equation*}
\begin{cases}
7x - 2y = 15 &\\
2x + y = 9 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
7x - 2y = 15 &\\
y = 9 - 2x &
\end{cases}
\end{equation*}$
7x − 2 * (9 − 2x) = 15
7x − 18 + 4x = 15
11x = 15 + 18
11x = 33
x = 33 : 11
x = 3
y = 9 − 2x = 9 − 2 * 3 = 9 − 6 = 3
Ответ: (3;3)
$\begin{equation*}
\begin{cases}
x + 3y = 2 &\\
2x + 3y = 7 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 2 - 3y &\\
2x + 3y = 7 &
\end{cases}
\end{equation*}$
2 * (2 − 3y) + 3y = 7
4 − 6y + 3y = 7
−3y = 7 − 4
−3y = 3
y = 3 : (−3)
y = −1
x = 2 − 3y = 2 − 3 * (−1) = 2 + 3 = 5
Ответ: (5;−1)
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