Дана функция y = f(x), где $f(x) = x^2$. Найдите:
а) $f(-5), f(7) + 1, f(5) - 4, f(7) - f(5)$;
б) $f(2x + 5), f(2x) + 5, 2f(x) + 5, 2f(x + 5)$;
в) $f(x^2), f(x^2 - 2), f(x^2) - 2, f((x - 2)^2)$;
г) $f(-x^3), 3f(x^3), f(3x^3), (-f(3x))^3$.
$f(-5) = (-5)^2 = 25$
$f(7) + 1 = 7^2 + 1 = 49 + 1 = 50$
$f(5) - 4 = 5^2 - 4 = 25 - 4 = 21$
$f(7) - f(5) = 7^2 - 5^2 = 49 - 25 = 24$
$f(2x + 5) = (2x + 5)^2 = 4x^2 + 20x + 25$
$f(2x) + 5 = (2x)^2 + 5 = 4x^2 + 5$
$2f(x) + 5 = 2x^2 + 5$
$2f(x + 5) = 2(x + 5)^2 = 2(x^2 + 10x + 25) = 2x^2 + 20x + 50$
$f(x^2) = (x^2)^2 = x^4$
$f(x^2 - 2) = (x^2 - 2)^2 = x^4 - 4x^2 + 4$
$f(x^2) - 2 = (x^2)^2 - 2 = x^4 - 2$
$f((x - 2)^2) = ((x - 2)^2)^2 = (x - 2)^4$
$f(-x^3) = (-x^3)^2 = x^6$
$3f(x^3) = 3(x^3)^2 = 3x^6$
$f(3x^3) = (3x^3)^2 = 9x^6$
$(-f(3x))^3 = (-(3x)^2)^3 = (-9x^2)^3 = -729x^6$
Пожауйста, оцените решение