Решите уравнение:
1) $(3x + 2)^2 + (4x - 1)(4x + 1) = (5x - 1)^2$;
2) $2(m + 1)^2 + 3(m - 1)^2 - 5(m + 1)(m - 1) = -4$.
$(3x + 2)^2 + (4x - 1)(4x + 1) = (5x - 1)^2$
$9x^2 + 12x + 4 + 16x^2 - 1 = 25x^2 - 10x + 1$
$9x^2 + 16x^2 - 25x^2 + 12x + 10x = 1 - 4 + 1$
22x = −2
$x = -\frac{2}{22} = -\frac{1}{11}$
$2(m + 1)^2 + 3(m - 1)^2 - 5(m + 1)(m - 1) = -4$
$2(m^2 + 2m + 1) + 3(m^2 - 2m + 1) - 5(m^2 - 1) = -4$
$2m^2 + 4m + 2 + 3m^2 - 6m + 3 - 5m^2 + 5 = -4$
$(2m^2 + 3m^2 - 5m^2) + (4m - 6m) = -4 - 2 - 3 - 5$
−2m = −14
m = −14 : −2
m = 7
Пожауйста, оцените решение