Решите уравнение:
1) $(x - 12)(x + 12) = 2(x - 6)^2 - x^2$;
2) $(3x - 1)^2 + (4x + 2)^2 = (5x - 1)(5x + 1)$;
3) $5(x + 2)^2 + (2x - 1)^2 - 9(x + 3)(x - 3) = 22$.
$(x - 12)(x + 12) = 2(x - 6)^2 - x^2$
$x^2 - 144 = 2(x^2 - 12x + 36) - x^2$
$x^2 - 144 = 2x^2 - 24x + 72 - x^2$
$x^2 + x^2 - 2x^2 + 24x = 144 + 72$
24x = 216
x = 216 : 24
x = 9
$(3x - 1)^2 + (4x + 2)^2 = (5x - 1)(5x + 1)$
$9x^2 - 6x + 1 + 16x^2 + 16x + 4 = 25x^2 - 1$
$9x^2 + 16x^2 - 25x^2 - 6x + 16x = -1 - 1 - 4$
10x = −6
x = −6 : 10
x = −0,6
$5(x + 2)^2 + (2x - 1)^2 - 9(x + 3)(x - 3) = 22$
$5(x^2 + 4x + 4) + (4x^2 - 4x + 1) - 9(x^2 - 9) = 22$
$5x^2 + 20x + 20 + 4x^2 - 4x + 1 - 9x^2 + 81 = 22$
$5x^2 + 4x^2 - 9x^2 + 20x - 4x = 22 - 20 - 1 - 81$
16x = −80
x = −80 : 16
x = −5
Пожауйста, оцените решение
