Выполните возведение в квадрат:
1) $(a + 8)^2$;
2) $(b - 2)^2$;
3) $(7 + c)^2$;
4) $(6 - d)^2$;
5) $(2m + 1)^2$;
6) $(4x - 3)^2$;
7) $(5m - 4n)^2$;
8) $(10c + 7d)^2$;
9) $(4x - \frac{1}{8}y)^2$;
10) $(0,3a + 0,9b)^2$;
11) $(c^2 - 6)^2$;
12) $(15 + k^2)^2$;
13) $(m^2 - 3n)^2$;
14) $(m^4 - n^3)^2$;
15) $(5a^4 -2a^7)^2$.
$(a + 8)^2 = a^2 + 2 * 8a + 8^2 = a^2 + 16a + 64$
$(b - 2)^2 = b^2 - 2 * 2b + 2^2 = b^2 - 4b + 4$
$(7 + c)^2 = 7^2 + 2 * 7c + c^2 = 49 + 14c + c^2$
$(6 - d)^2 = 6^2 - 2 * 6d + d^2 = 36 - 12d + d^2$
$(2m + 1)^2 = (2m)^2 + 2 * 1 * 2m + 1^2 = 4m^2 + 4m + 1$
$(4x - 3)^2 = (4x)^2 - 2 * 4 * 3x + 3^2 = 16x^2 - 24x + 9$
$(5m - 4n)^2 = (5m)^2 - 2 * 5 * 4mn + (4n)^2 = 25m^2 - 40mn + 16n^2$
$(10c + 7d)^2 = (10c)^2 + 2 * 10 * 7cd + (7d)^2 = 100c^2 + 140cd + 49d^2$
$(4x - \frac{1}{8}y)^2 = (4x)^2 - 2 * 4 * \frac{1}{8}xy + (\frac{1}{8}y)^2 = 16x^2 - xy + \frac{1}{64}y^2$
$(0,3a + 0,9b)^2 = (0,3a)^2 + 2 * 0,3 * 0,9ab + (0,9b)^2 = 0,09a^2 + 0,54ab + 0,81b^2$
$(c^2 - 6)^2 = (c^2)^2 - 2 * 6c^2 + 6^2 = c^4 - 12c^2 + 36$
$(15 + k^2)^2 = 15^2 + 2 * 15k^2 + (k^2)^2 = 225 + 30k^2 + k^4$
$(m^2 - 3n)^2 = (m^2)^2 - 2 * 3m^2n + (3n)^2 = m^4 - 6m^2n + 9n^2$
$(m^4 - n^3)^2 = (m^4)^2 - 2m^4n^3 + (n^3)^2 = m^8 - 2m^4n^3 + n^6$
$(5a^4 - 2a^7)^2 = (5a^4)^2 - 5 * 2 * 2a^4a^7 + (2a^7)^2 = 25a^8 - 20a^{11} + 4a^{14}$
Пожауйста, оцените решение