Выполните умножение:
1) $(x^3 + 4)(x^3 - 4)$;
2) $(ab - c)(ab + c)$;
3) $(x - y^2)(y^2 + x)$;
4) $(3m^2 - 2c)(3m^2 + 2c)$;
5) $(6a^3 - 8b)(6a^3 + 8b)$;
6) $(5n^4 - m^4)(5n^4 + m^4)$;
7) $(0,2m^8 - 0,8n^6)(0,2m^8 + 0,8n^6)$;
8) $(\frac{2}{7}p^7 + \frac{4}{11}k^9)(\frac{4}{11}k^9 - \frac{2}{7}p^7)$.
$(x^3 + 4)(x^3 - 4) = (x^3)^2 - 4^2 = x^6 - 16$
$(ab - c)(ab + c) = (ab)^2 - c^2 = a^2b^2 - c^2$
$(x - y^2)(y^2 + x) = x^2 - (y^2)^2 = x^2 - y^4$
$(3m^2 - 2c)(3m^2 + 2c) = (3m^2)^2 - (2c)^2 = 9m^4 - 4c^2$
$(6a^3 - 8b)(6a^3 + 8b) = (6a^3)^2 - (8b)^2 = 36a^6 - 64b^2$
$(5n^4 - m^4)(5n^4 + m^4) = (5n^4)^2 - (m^4)^2 = 25n^8 - m^8$
$(0,2m^8 - 0,8n^6)(0,2m^8 + 0,8n^6) = (0,2m^8)^2 - (0,8n^6)^2 = 0,04m^{16} - 0,64n^{12}$
$(\frac{2}{7}p^7 + \frac{4}{11}k^9)(\frac{4}{11}k^9 - \frac{2}{7}p^7) = (\frac{4}{11}k^9)^2 - (\frac{2}{7}p^7)^2 = \frac{16}{121}k^{18} - \frac{4}{49}p^{14}$
Пожауйста, оцените решение