Решите уравнение:
1) $\frac{x - 7}{4} - \frac{x}{6} = 2$;
2) $\frac{x + 6}{2} - \frac{x - 7}{7} = 4$;
3) $\frac{2x + 3}{6} + \frac{1 - 4x}{8} = \frac{1}{3}$;
4) $3x - \frac{2x + 3}{2} = \frac{x + 6}{3}$;
5) $\frac{6x - 7}{5} - \frac{3x + 1}{6} = \frac{11 - x}{15}$;
6) $\frac{5x - 3}{9} - \frac{4x + 3}{6} = x - 1$;
7) $\frac{8x - 5}{3} - \frac{4x + 3}{4} + \frac{2 - 9x}{2} = -3$;
8) $\frac{8x^2 - 3x}{16} - \frac{6x^2 + 1}{12} = -1$.
$\frac{x - 7}{4} - \frac{x}{6} = 2$
$\frac{3(x - 7) - 2x}{12} = 2$
3(x − 7) − 2x = 2 * 12
3x − 21 − 2x = 24
3x − 2x = 24 + 21
x = 45
$\frac{x + 6}{2} - \frac{x - 7}{7} = 4$
$\frac{7(x + 6) - 2(x - 7)}{14} = 4$
7(x + 6) − 2(x − 7) = 4 * 14
7x + 42 − 2x + 14 = 56
7x − 2x = 56 − 42 − 14
5x = 0
x = 0
$\frac{2x + 3}{6} + \frac{1 - 4x}{8} = \frac{1}{3}$
$\frac{4(2x + 3) + 3(1 - 4x)}{24} = \frac{1}{3}$
$4(2x + 3) + 3(1 - 4x) = \frac{1}{3} * 24$
8x + 12 + 3 − 12x = 8
8x − 12x = 8 − 12 − 3
−4x = −7
$x = \frac{7}{4} = 1\frac{3}{4}$
x = 1,25
$3x - \frac{2x + 3}{2} = \frac{x + 6}{3}$
$3x - \frac{2x + 3}{2} - \frac{x + 6}{3} = 0$
$\frac{6 * 3x - 3(2x + 3) - 2(x + 6)}{6} = 0$
6 * 3x − 3(2x + 3) − 2(x + 6) = 0
18x − 6x − 9 − 2x − 12 = 0
18x − 6x − 2x = 9 + 12
10x = 21
x = 21 : 10
x = 2,1
$\frac{6x - 7}{5} - \frac{3x + 1}{6} = \frac{11 - x}{15}$
$\frac{6x - 7}{5} - \frac{3x + 1}{6} - \frac{11 - x}{15} = 0$
$\frac{6(6x - 7) - 5(3x + 1) - 2(11 - x)}{30} = 0$
6(6x − 7) − 5(3x + 1) − 2(11 − x) = 0
36x − 42 − 15x − 5 − 22 + 2x = 0
36x − 15x + 2x = 42 + 5 + 22
23x = 69
x = 69 : 23
x = 3
$\frac{5x - 3}{9} - \frac{4x + 3}{6} = x - 1$
$\frac{5x - 3}{9} - \frac{4x + 3}{6} - x = -1$
$\frac{2(5x - 3) - 3(4x + 3) - 18x}{18} = -1$
2(5x − 3) − 3(4x + 3) − 18 = −1 * 18
2(5x − 3) − 3(4x + 3) − 18 = −18
10x − 6 − 12x − 9 − 18x = −18
10x − 12x − 18x = 6 + 9 − 18
−20x = −3
$x = \frac{3}{20}$
$\frac{8x - 5}{3} - \frac{4x + 3}{4} + \frac{2 - 9x}{2} = -3$
$\frac{4(8x - 5) - 3(4x + 3) + 6(2 - 9x)}{12} = -3$
4(8x − 5) − 3(4x + 3) + 6(2 − 9x) = −3 * 12
32x − 20 − 12x − 9 + 12 − 54x = −36
32x − 12x − 54x = −36 + 20 + 9 − 12
−34x = −19
$x = \frac{19}{34}$
$\frac{8x^2 - 3x}{16} - \frac{6x^2 + 1}{12} = -1$
$\frac{3(8x^2 - 3x) - 4(6x^2 + 1)}{48} = -1$
$3(8x^2 - 3x) - 4(6x^2 + 1) = -1 * 48$
$24x^2 - 9x - 24x^2 - 4 = -48$
−9x = −48 + 4
−9x = −44
$x = \frac{44}{9} = 4\frac{8}{9}$
Пожауйста, оцените решение