Решите уравнение:
1) $(x - 8)^2 - (x - 4)(x + 4) = 0$;
2) $(4x - 5)(4x + 5) - (4x - 1)^2 = 9 - 2x$.
$(x - 8)^2 - (x - 4)(x + 4) = 0$
$x^2 - 16x + 64 - (x^2 - 16) = 0$
$x^2 - 16x + 64 - x^2 + 16 = 0$
$x^2 - x^2 - 16x = -64 - 16$
−16x = −80
x = −80 : −16
x = 5
$(4x - 5)(4x + 5) - (4x - 1)^2 = 9 - 2x$
$16x^2 - 25 - (16x^2 - 8x + 1) = 9 - 2x$
$16x^2 - 16x^2 + 8x + 2x = 9 + 25 + 1$
10x = 35
x = 35 : 10
x = 3,5
Пожауйста, оцените решение