Найдите корень уравнения:
а) $\frac{6x - 5}{7} = \frac{2x - 1}{3} + 2$;
б) $\frac{5 - x}{2} + \frac{3x - 1}{5} = 4$;
в) $\frac{5x - 7}{12} - \frac{x - 5}{8} = 5$;
г) $\frac{4y - 11}{15} + \frac{13 - 7y}{20} = 2$;
д) $\frac{5 - 6y}{3} + \frac{y}{8} = 0$;
е) $\frac{y}{4} - \frac{3 - 2y}{5} = 0$.
$\frac{6x - 5}{7} = \frac{2x - 1}{3} + 2$ |*21
3(6x − 5) = 7(2x − 1) + 42
18x − 15 = 14x − 7 + 42
18x − 14x = 35 + 15
4x = 50
$x = \frac{50}{4} = \frac{25}{2}$
x = 12,5
$\frac{5 - x}{2} + \frac{3x - 1}{5} = 4$ |*10
5(5 − x) + 2(3x − 1) = 40
25 − 5x + 6x − 2 = 40
x = 40 − 25 + 2
x = 17
$\frac{5x - 7}{12} - \frac{x - 5}{8} = 5$ |*24
2(5x − 7) − 3(x − 5) = 120
10x − 14 − 3x + 15 = 120
7x = 120 + 14 − 15
7x = 119
x = 119 : 7
x = 17
$\frac{4y - 11}{15} + \frac{13 - 7y}{20} = 2$ |*60
4(4y − 11) + 3(13 − 7y) = 120
16y − 44 + 39 − 21y = 120
−5y = 120 + 44 − 39
−5y = 125
y = 125 : (−5)
y = −25
$\frac{5 - 6y}{3} + \frac{y}{8} = 0$ |*24
8(5 − 6y) + 3y = 0
40 − 48y + 3y = 0
−45y = −40
$y = \frac{40}{45} = \frac{8}{9}$
$\frac{y}{4} - \frac{3 - 2y}{5} = 0$ |*20
5y − 4(3 − 2y) = 0
5y − 12 + 8y = 0
13y = 12
$y = \frac{12}{13}$
Пожауйста, оцените решение