Решите уравнение:
а) $\frac{x}{4} + \frac{x}{3} = 14$;
б) $\frac{a}{2} - \frac{a}{8} = 5$;
в) $\frac{y}{4} = y - 1$;
г) $2z + 3 = \frac{2z}{5}$;
д) $\frac{2c}{3} - \frac{4c}{5} = 7$;
е) $\frac{5x}{9} + \frac{x}{3} + 4 = 0$;
ж) $\frac{4a}{9} + 1 = \frac{5a}{12}$;
з) $\frac{5m}{12} - \frac{m}{8} = \frac{1}{3}$;
и) $\frac{3n}{14} + \frac{n}{2} = \frac{2}{7}$.
$\frac{x}{4} + \frac{x}{3} = 14$ |*12
3x + 4x = 168
7x = 168
x = 168 : 7
x = 24
$\frac{a}{2} - \frac{a}{8} = 5$ |*8
4a − a = 40
3a = 40
$a = \frac{40}{3} = 13\frac{1}{3}$
$\frac{y}{4} = y - 1$ |*4
y = 4(y − 1)
y = 4y − 4
y − 4y = −4
−3y = −4
$y = \frac{4}{3} = 1\frac{1}{3}$
$2z + 3 = \frac{2z}{5}$ |*5
5(2z + 3) = 2z
10z + 15 = 2z
10z − 2z = −15
8z = −15
$z = -\frac{15}{8} = -1\frac{7}{8}$
$\frac{2c}{3} - \frac{4c}{5} = 7$ |*15
10c − 12c = 105
−2c = 105
$c = -\frac{105}{2}$
c = −52,5
$\frac{5x}{9} + \frac{x}{3} + 4 = 0$ |*9
5x + 3x + 36 = 0
8x = −36
$x = -\frac{36}{8} = -\frac{9}{2}$
x = −4,5
$\frac{4a}{9} + 1 = \frac{5a}{12}$ |*36
16a + 36 = 15a
16a − 15a = −36
a = −36
$\frac{5m}{12} - \frac{m}{8} = \frac{1}{3}$ |*24
10m − 3m = 8
7m = 8
$m = \frac{8}{7} = 1\frac{1}{7}$
$\frac{3n}{14} + \frac{n}{2} = \frac{2}{7}$ |*14
3n + 7n = 4
10n = 4
$n = \frac{4}{10} = 0,4$
Пожауйста, оцените решение