Разложите на множители:
а) $(x - 5)^2 - 16$;
б) $(b + 7)^2 - 9$;
в) $25 - (3 - x)^2$;
г) $81 - (a + 7)^2$;
д) $(7x - 4)^2 - (2x + 1)^2$;
е) $(n - 2)^2 - (3n + 1)^2$;
ж) $9(a + 1)^2 - 1$;
з) $4 - 25(x - 3)^2$.
$(x - 5)^2 - 16 = (x - 5 - 4)(x - 5 + 4) = (x - 9)(x - 1)$
$(b + 7)^2 - 9 = (b + 7 - 3)(b + 7 + 3) = (b + 4)(b + 10)$
$25 - (3 - x)^2 = (5 - 3 + x) = (5 + 3 - x) = (2 + x)(8 - x)$
$81 - (a + 7)^2 = (9 - a - 7)(9 + a + 7) = (2 - a)(16 + a)$
$(7x - 4)^2 - (2x + 1)^2 = (7x - 4 - 2x - 1)(7x - 4 + 2x + 1) = (5x - 5)(9x - 3) = 15(x - 1)(3x - 1)$
$(n - 2)^2 - (3n + 1)^2 = (n - 2 - 3n - 1)(n - 2 + 3n + 1) = (-2n - 3)(4n - 1)$
$9(a + 1)^2 - 1 = 3^2 * (a + 1)^2 - 1 = (3a + 3)^2 - 1 = (3a + 3 - 1)(3a + 3 + 1) = (3a + 2)(3a + 4)$
$4 - 25(x - 3)^2 = 4 - 5^2(x - 3)^2 = 4 - (5x - 15)^2 = (2 - 5x + 15)(2 + 5x - 15)$
Пожауйста, оцените решение