Решите уравнение:
а) (x − 2)(x − 3) = x(x + 1);
б) $(x + 4)(x + 6) - x^2 = 30$;
в) $(x - 5)(x + 1) - x = x^2 + 5$;
г) (x − 1)(x − 3) = (x − 2)(x − 4).
(x − 2)(x − 3) = x(x + 1)
$x^2 - 2x - 3x + 6 = x^2 + x$
$x^2 - 5x - x^2 - x = -6$
−6x = −6
x = 1
$(x + 4)(x + 6) - x^2 = 30$
$x^2 + 4x + 6x + 24 - x^2 = 30$
10x = 30 − 24
10x = 6
x = 0,6
$(x - 5)(x + 1) - x = x^2 + 5$
$x^2 - 5x + x - 5 - x - x^2 = 5$
−5x = 5 + 5
−5x = 10
x = −2
(x − 1)(x − 3) = (x − 2)(x − 4)
$x^2 - x - 3x + 3 = x^2 - 2x - 4x + 8$
$x^2 - 4x + 2x + 4x - x^2 = 8 - 3$
2x = 5
x = 2,5
Пожауйста, оцените решение
