Вычислите:
а) $\frac{5^{12} * (5^4)^2}{(5^5)^4}$;
б) $\frac{2^{6} * (2^3)^5}{64^4}$;
в) $\frac{(3^3)^{2} * 27}{81^2}$;
г) $\frac{25^{6}}{(5^3)^3 * 125}$.
$\frac{5^{12} * (5^4)^2}{(5^5)^4} = \frac{5^{12} * 5^8}{5^{20}} = \frac{5^{20}}{5^{20}} = 1$
$\frac{2^{6} * (2^3)^5}{64^4} = \frac{2^{6} * 2^{15}}{(2^6)^4} = \frac{2^{21}}{2^{24}} = \frac{1}{2^{3}} = \frac{1}{8}$
$\frac{(3^3)^{2} * 27}{81^2} = \frac{3^6 * 3^3}{(3^4)^2} = \frac{3^{9}}{3^8} = 3^1 = 3$
$\frac{25^{6}}{(5^3)^3 * 125} = \frac{(5^2)^{6}}{5^9 * 5^3} = \frac{5^{12}}{5^{12}} = 1$
Пожауйста, оцените решение
