$\frac{1}{5}(x + 4) = 3$ |* 5
x + 4 = 15
x = 15 − 4
x = 11

$\frac{1}{4}(2y + 1) = 8$ |* 4
2y + 1 = 32
2y = 32 − 1
2y = 31
y = 31 : 2
y = 15,5

$-\frac{1}{7}(5u - 7) = 6$ |* (−7)
5u − 7 = −42
5u = −42 + 7
5u = −35
u = −35 : 5
u = −7

$\frac{2}{3}(10 - c) = -8$ |* 3
2(10 − c) = −24
20 − 2c = −24
−2c = −24 − 20
−2c = −44
c = 44 : 2
c = 22

$2t = 1\frac{1}{3}(t + 5)$
$2t = \frac{4}{3}(t + 5)$ |* 3
6t = 4(t + 5)
6t = 4t + 20
6t − 4t = 20
2t = 20
t = 20 : 2
t = 10

$1\frac{1}{4}(x - 2) = -5(x + 1)$
$\frac{5}{4}(x - 2) = -5(x + 1)$ |* 4
5(x − 2) = −20(x + 1)
5x − 10 = −20x − 20
5x + 20x = −20 + 10
25x = −10
x = −10 : 25
x = −0,4