Решение:
а) $7\frac{2}{9} * 8\frac{2}{3} - 7\frac{2}{9} * 6\frac{2}{3} = 7\frac{2}{9} * (8\frac{2}{3} - 6\frac{2}{3}) = \frac{65}{9} * 2 = \frac{130}{9} = 14\frac{4}{9};$
б) $12\frac{35}{44} * 4\frac{1}{10} - 8\frac{35}{44} * 4\frac{1}{10} = 4\frac{1}{10} * (12\frac{35}{44} - 8\frac{35}{44}) = \frac{41}{10} * 4 = \frac{41 * 2}{5} = \frac{82}{5} = 16\frac{2}{5};$
в) $7\frac{1}{3} * 2\frac{1}{5} + 7\frac{1}{3} * 1\frac{4}{5} = 7\frac{1}{3} * (2\frac{1}{5} + 1\frac{4}{5}) = \frac{22}{3} * 4 = \frac{88}{3} = 29\frac{1}{3};$
г) $(-3\frac{1}{9}) * 7\frac{4}{7} + (-3\frac{1}{9}) * (-2\frac{3}{7}) = (-3\frac{1}{9}) * (7\frac{4}{7} + (-2\frac{3}{7})) = (-\frac{28}{9}) * 5\frac{1}{7} = (-\frac{28}{9}) * \frac{36}{7} = -\frac{28 * 36}{9 * 7} = -\frac{4 * 4}{1 * 1} = -16;$
д) $2\frac{6}{7} * 4\frac{2}{5} - 2\frac{6}{7} * 4 = 2\frac{6}{7} * (4\frac{2}{5} - 4) = \frac{20}{7} * \frac{2}{5} = \frac{20 * 2}{7 * 5} = \frac{4 * 2}{7 * 1} = \frac{8}{7} = 1\frac{1}{7};$
е) $(-2\frac{3}{7}) * (-5) + 2\frac{3}{7} * (-2\frac{2}{3}) = 2\frac{3}{7} * (5 - 2\frac{2}{3}) = \frac{17}{7} * 2\frac{1}{3} = \frac{17}{7} * \frac{7}{3} = \frac{17}{3} = 5\frac{2}{3}.$
Ответ:
а) $14\frac{4}{9};$
б) $16\frac{2}{5};$
в) $29\frac{1}{3};$
г) $-16;$
д) $1\frac{1}{7};$
е) $5\frac{2}{3}.$