Вычислите:
а) $2\frac{13}{30} - (1\frac{1}{10} + \frac{1}{5})$;
б) $2\frac{8}{15} - (1\frac{3}{10} + \frac{2}{5})$;
в) $4\frac{14}{45} - 1\frac{7}{15} - \frac{3}{5}$;
г) $4\frac{11}{30} - 2\frac{9}{20} - \frac{1}{10}$.
$2\frac{13}{30} - (1\frac{1}{10} + \frac{1}{5}) = 2\frac{13}{30} - (1\frac{1}{10} + \frac{2}{10}) = 2\frac{13}{30} - 1\frac{3}{10} = 2\frac{13}{30} - 1\frac{9}{30} = 1\frac{4}{30} = 1\frac{2}{15}$
$2\frac{8}{15} - (1\frac{3}{10} + \frac{2}{5}) = 2\frac{8}{15} - (1\frac{3}{10} + \frac{4}{10}) = 2\frac{8}{15} - 1\frac{7}{10} = 2\frac{16}{30} - 1\frac{21}{30} = 1\frac{46}{30} - 1\frac{21}{30} = \frac{25}{30} = \frac{5}{6}$
$4\frac{14}{45} - 1\frac{7}{15} - \frac{3}{5} = 4\frac{14}{45} - 1\frac{21}{45} - \frac{27}{45} = 3\frac{59}{45} - 1\frac{21}{45} - \frac{27}{45} = 2\frac{38}{45} - \frac{27}{45} = 2\frac{11}{45}$
$4\frac{11}{30} - 2\frac{9}{20} - \frac{1}{10} = 4\frac{22}{60} - 2\frac{27}{60} - \frac{6}{60} = 3\frac{82}{60} - 2\frac{27}{60} - \frac{6}{60} = 1\frac{55}{60} - \frac{6}{60} = 1\frac{49}{60}$
Пожауйста, оцените решение
