Решите уравнение:
1) $x + 4\frac{4}{19} = 6\frac{2}{19}$;
2) $25 - x = 8\frac{3}{14}$;
3) $32 - x = 9\frac{18}{35}$.
$x + 4\frac{4}{19} = 6\frac{2}{19}$
$x = 6\frac{2}{19} - 4\frac{4}{19}$
$x = 5\frac{21}{19} - 4\frac{4}{19}$
$x = 1\frac{17}{19}$
$25 - x = 8\frac{3}{14}$
$-x = 8\frac{3}{14} - 25$
$x = 25 - 8\frac{3}{14}$
$x = 24\frac{14}{14} - 8\frac{3}{14}$
$x = 16\frac{11}{14}$
$32 - x = 9\frac{18}{35}$
$-x = 9\frac{18}{35} - 32$
$x = 32 - 9\frac{18}{35}$
$x = 31\frac{35}{35} - 9\frac{18}{35}$
$x = 22\frac{17}{35}$
Пожауйста, оцените решение