Выполните сложение:
а) $3\frac{1}{2} + \frac{1}{2}$;
б) $4\frac{1}{3} + 1\frac{2}{3}$;
в) $2\frac{3}{8} + 3\frac{5}{8}$;
г) $3\frac{2}{3} + 1\frac{2}{3}$;
д) $\frac{5}{7} + 5\frac{4}{7}$;
е) $5\frac{2}{9} + 2\frac{1}{9}$.
$3\frac{1}{2} + \frac{1}{2} = 3 + (\frac{1}{2} + \frac{1}{2}) = 3 + \frac{2}{2} = 3 + 1 = 4$
$4\frac{1}{3} + 1\frac{2}{3} = (4 + 1) + (\frac{1}{3} + \frac{2}{3}) = 5 + \frac{3}{3} = 5 + 1 = 6$
$2\frac{3}{8} + 3\frac{5}{8} = (2 + 3) + (\frac{3}{8} + \frac{5}{8}) = 5 + \frac{8}{8} = 5 + 1 = 6$
$3\frac{2}{3} + 1\frac{2}{3} = (3 + 1) + (\frac{2}{3} + \frac{2}{3}) = 4 + \frac{4}{3} = 4 + 1\frac{1}{3} = (4 + 1) + \frac{1}{3} = 5\frac{1}{3}$
$\frac{5}{7} + 5\frac{4}{7} = 5 + (\frac{5}{7} + \frac{4}{7}) = 5 + \frac{9}{7} = 5 + 1\frac{2}{7} = (5 + 1) + \frac{2}{7} = 6 + \frac{2}{7} = 6\frac{2}{7}$
$5\frac{2}{9} + 2\frac{1}{9} = (5 + 2) + (\frac{2}{9} + \frac{1}{9}) = 7 + \frac{3}{9} = 7 + \frac{1}{3} = 7\frac{1}{3}$
Пожауйста, оцените решение