Дано:
$NH_{2} - CH_{2}-CH_{2}-COOH$
Найти:
ω (C) − ?
ω (H) − ?
ω (O) − ?
ω (N) − ?
Решение:
M ($NH_{2} - CH_{2}-CH_{2}-COOH$) = 14 + 2 * 1 + 12 + 2 * 1 + 12 + 2 * 1 + 12 + 16 + 16 + 1 = 89 г/моль
ω (C) = $\frac{3\; * \;12}{89}$ * 100% = 40%
ω (H) = $\frac{7\; * \;1}{89}$ * 100% = 7,9%
ω (O) = $\frac{2\; * \;16}{89}$ * 100% = 36%
ω (N) = $\frac{1\; * \;14}{89}$ * 100% = 16,1%
Ответ: ω (C) = 40%; ω (H) = 7,9%; ω (O) = 36%; ω (N) = 16,1%.