$6x^2 - 2 = 5 - x$
$6x^2 - 2 - 5 + x = 0$
$6x^2 + x - 7 = 0$
$D = b^2 - 4ac = 1^2 - 4 * 6 * (-7) = 1 + 168 = 169 > 0$
$x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{-1 + \sqrt{169}}{2 * 6} = \frac{-1 + 13}{12} = \frac{12}{12} = 1$
$x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{-1 - \sqrt{169}}{2 * 6} = \frac{-1 - 13}{12} = \frac{-14}{12} = -\frac{7}{6} = -1\frac{1}{6}$
Ответ: при $x = -1\frac{1}{6}$ и x = 1

$y - 6 = y^2 - 9y + 3$
$y - 6 - y^2 + 9y - 3 = 0$
$-y^2 + 10y - 9 = 0$
$D = b^2 - 4ac = 10^2 - 4 * (-1) * (-9) = 100 - 36 = 64 > 0$
$y_1 = \frac{-b + \sqrt{D}}{2a} = \frac{-10 + \sqrt{64}}{2 * (-1)} = \frac{-10 + 8}{-2} = \frac{-2}{-2} = 1$
$y_2 = \frac{-b - \sqrt{D}}{2a} = \frac{-10 - \sqrt{64}}{2 * (-1)} = \frac{-10 - 8}{-2} = \frac{-18}{-2} = 9$
Ответ: при y = 1 и y = 9

$4m^2 + 4m + 2 = 2m^2 + 10m + 8$
$4m^2 + 4m + 2 - 2m^2 - 10m - 8 = 0$
$2m^2 - 6m - 6 = 0$ |: 2
$m^2 - 3m - 3 = 0$
$D = b^2 - 4ac = (-3)^2 - 4 * 1 * (-3) = 9 + 12 = 21 > 0$
$m_1 = \frac{-b + \sqrt{D}}{2a} = \frac{3 + \sqrt{21}}{2 * 1} = \frac{3 + \sqrt{21}}{2}$
$m_2 = \frac{-b - \sqrt{D}}{2a} = \frac{3 - \sqrt{21}}{2} = \frac{3 - \sqrt{21}}{2}$
Ответ: при $m = \frac{3 - \sqrt{21}}{2}$ и $m = \frac{3 + \sqrt{21}}{2}$