Представьте в виде дроби выражение:
1) $\frac{7k}{18p} - \frac{4k}{18p}$;
2) $\frac{a - b}{2b} - \frac{a}{2b}$;
3) $-\frac{a - 12b}{27a} + \frac{a + 15b}{27a}$;
4) $\frac{x - 7y}{xy} - \frac{x - 4y}{xy}$;
5) $\frac{10a + 6b}{11a^3} - \frac{6b - a}{11a^3}$;
6) $\frac{x^2 - xy}{x^2y} + \frac{2xy - 3x^2}{x^2y}$.
$\frac{7k}{18p} - \frac{4k}{18p} = \frac{7k - 4k}{18p} = \frac{3k}{18p} = \frac{k}{6p}$
$\frac{a - b}{2b} - \frac{a}{2b} = \frac{a - b - a}{2b} = \frac{-b}{2b} = -\frac{1}{2}$
$-\frac{a - 12b}{27a} + \frac{a + 15b}{27a} = \frac{-(a - 12b) + a + 15b}{27a} = \frac{-a + 12b + a + 15b}{27a} = \frac{27b}{27a} = \frac{b}{a}$
$\frac{x - 7y}{xy} - \frac{x - 4y}{xy} = \frac{x - 7y - (x - 4y)}{xy} = \frac{x - 7y - x + 4y}{xy} = \frac{-3y}{xy} = -\frac{3}{x}$
$\frac{10a + 6b}{11a^3} - \frac{6b - a}{11a^3} = \frac{10a + 6b - (6b - a)}{11a^3} = \frac{10a + 6b - 6b + a}{11a^3} = \frac{11a}{11a^3} = \frac{1}{a^2}$
$\frac{x^2 - xy}{x^2y} + \frac{2xy - 3x^2}{x^2y} = \frac{x^2 - xy + 2xy - 3x^2}{x^2y} = \frac{xy - 2x^2}{x^2y} = \frac{x(y - 2x)}{x^2y} = \frac{y - 2x}{xy}$
Пожауйста, оцените решение