$\frac{\sqrt{75}}{\sqrt{3}}=\sqrt{\frac{75}{3}}=\sqrt{25}=5$

$\frac{\sqrt{98}}{\sqrt{2}}=\sqrt{\frac{98}{2}}=\sqrt{49}=7$

$\frac{\sqrt{3}}{\sqrt{48}}=\sqrt{\frac{3}{48}}=\sqrt{\frac{1}{16}}=\frac{1}{4}$

$\frac{\sqrt{3,2}}{\sqrt{0,2}}=\sqrt{\frac{3,2}{0,2}}=\sqrt{\frac{32}{2}}=\sqrt{16}=4$

$\frac{\sqrt{72}}{\sqrt{50}}=\sqrt{\frac{72}{50}}=\sqrt{\frac{36}{25}}=\frac{6}{5}=1\frac{1}{5}$

$\frac{\sqrt{27}}{\sqrt{147}}=\sqrt{\frac{27}{147}}=\sqrt{\frac{9}{49}}=\frac{3}{7}$

$\frac{\sqrt{6}\ast <!--\; \ast \; -->\sqrt{3}}{\sqrt{2}}=\frac{\sqrt{6\ast <!--\; \ast \; -->3}}{\sqrt{2}}=\frac{\sqrt{18}}{\sqrt{2}}=\sqrt{\frac{18}{2}}=\sqrt{9}=3$

$\frac{\sqrt{5}}{\sqrt{3}\ast <!--\; \ast \; -->\sqrt{15}}=\frac{\sqrt{5}}{\sqrt{3\ast <!--\; \ast \; -->15}}=\frac{\sqrt{5}}{\sqrt{45}}=\sqrt{\frac{5}{45}}=\sqrt{\frac{1}{9}}=\frac{1}{3}$