$\frac{3^{10}\ast <!--\; \ast \; -->{27}^3}{9^9}=\frac{3^{10}\ast <!--\; \ast \; -->(3^3{)}^3}{(3^2{)}^9}=\frac{3^{10}\ast <!--\; \ast \; -->3^9}{3^{18}}=\frac{3^{19}}{3^{18}}=3$

$(5\frac{1}{3}{)}^7\ast <!--\; \ast \; -->(\frac{3}{16}{)}^8=(\frac{16}{3}{)}^7\ast <!--\; \ast \; -->(\frac{3}{16}{)}^8=\frac{{16}^7}{3^7}\ast <!--\; \ast \; -->\frac{3^8}{{16}^8}=\frac{3}{16}$