Представьте числа $1, 3, 9, 27, 81, \frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \frac{1}{81}$ в виде степени с основанием:
1) 3;
2) $\frac{1}{3}$.
$1 = 3^0$
$3 = 3^1$
$9 = 3 * 3 = 3^2$
$27 = 3 * 3 * 3 = 3^3$
$81 = 3 * 3 * 3 * 3 = 3^4$
$\frac{1}{3} = 3^{-1}$
$\frac{1}{9} = \frac{1}{3^2} = 3^{-2}$
$\frac{1}{27} = \frac{1}{3^3} = 3^{-3}$
$\frac{1}{81} = \frac{1}{3^4} = 3^{-4}$
$1 = (\frac{1}{3})^0$
$3 = (\frac{1}{3})^{-1}$
$9 = 3^2 = (\frac{1}{3})^{-2}$
$27 = 3^3 = (\frac{1}{3})^{-3}$
$81 = 3^4 = (\frac{1}{3})^{-4}$
$\frac{1}{3} = (\frac{1}{3})^{1}$
$\frac{1}{9} = \frac{1}{3^2} = (\frac{1}{3})^{2}$
$\frac{1}{27} = \frac{1}{3^3} = (\frac{1}{3})^{3}$
$\frac{1}{81} = \frac{1}{3^4} = (\frac{1}{3})^{4}$
Пожауйста, оцените решение
