Решите уравнение:
1) $\frac{x - 6}{x - 4} = 0$;
2) $\frac{x - 2}{x^2 - 4} = 0$;
3) $\frac{x^2 - 4}{x - 2} = 0$;
4) $\frac{x - 2}{x - 2} = 1$;
5) $\frac{2x^2 + 18}{x^2 + 9} = 2$;
6) $\frac{x}{x - 5} + \frac{2x - 9}{x - 5} = 0$;
7) $\frac{5x - 7}{x + 1} - \frac{x - 5}{x + 1} = 0$;
8) $\frac{2x + 16}{x + 3} - \frac{1 - 3x}{x + 3} = 0$;
9) $\frac{2}{x - 1} + \frac{1}{x + 1} = 0$;
10) $\frac{3}{x - 2} = \frac{4}{x + 3}$;
11) $\frac{x}{x - 6} = 2$;
12) $\frac{x - 4}{x - 3} = \frac{2x + 1}{2x - 1}$;
13) $\frac{x + 8}{x} - \frac{6}{x - 2} = 0$;
14) $\frac{2x}{x - 5} - \frac{x^2 + 15x}{x^2 - 25} = 0$;
15) $3 - \frac{2x^2 - 5x}{x^2 - 3x} = 0$.
$\frac{x - 6}{x - 4} = 0$
$\begin{equation*}
\begin{cases}
x - 6 = 0 &\\
x - 4 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 6 &\\
x ≠ 4 &
\end{cases}
\end{equation*}$
Ответ: x = 6
$\frac{x - 2}{x^2 - 4} = 0$
$\begin{equation*}
\begin{cases}
x - 2 = 0 &\\
x^2 - 4 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 2 &\\
x^2 ≠ 4 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 2 &\\
x ≠ ±2 &
\end{cases}
\end{equation*}$
Ответ: нет корней
$\frac{x^2 - 4}{x - 2} = 0$
$\begin{equation*}
\begin{cases}
x^2 - 4 = 0 &\\
x - 2 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x^2 = 4 &\\
x ≠ 2 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = ±2 &\\
x ≠ 2 &
\end{cases}
\end{equation*}$
Ответ: x = −2
$\frac{x - 2}{x - 2} = 1$
1 = 1
$\begin{equation*}
\begin{cases}
1 = 1 &\\
x - 2 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
1 = 1 &\\
x ≠ 2 &
\end{cases}
\end{equation*}$
Ответ: x − любое число, кроме 2.
$\frac{2x^2 + 18}{x^2 + 9} = 2$
$\frac{2(x^2 + 9)}{x^2 + 9} = 2$
2 = 2
$\begin{equation*}
\begin{cases}
2 = 2 &\\
x^2 + 9 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
2 = 2 &\\
x^2 ≠ -9 &
\end{cases}
\end{equation*}$
Ответ: x − любое число.
$\frac{x}{x - 5} + \frac{2x - 9}{x - 5} = 0$
$\frac{x + 2x - 9}{x - 5} = 0$
$\frac{3x - 9}{x - 5} = 0$
$\begin{equation*}
\begin{cases}
3x - 9 = 0 &\\
x - 5 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
3x = 9 &\\
x ≠ 5 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 3 &\\
x ≠ 5 &
\end{cases}
\end{equation*}$
Ответ: x = 3
$\frac{5x - 7}{x + 1} - \frac{x - 5}{x + 1} = 0$
$\frac{5x - 7 - (x - 5)}{x + 1} = 0$
$\frac{5x - 7 - x + 5}{x + 1} = 0$
$\frac{4x - 2}{x + 1} = 0$
$\begin{equation*}
\begin{cases}
4x - 2 = 0 &\\
x + 1 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
4x = 2 &\\
x ≠ -1 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 0,5 &\\
x ≠ -1 &
\end{cases}
\end{equation*}$
Ответ: x = 0,5
$\frac{2x + 16}{x + 3} - \frac{1 - 3x}{x + 3} = 0$
$\frac{2x + 16 - (1 - 3x)}{x + 3} = 0$
$\frac{2x + 16 - 1 + 3x}{x + 3} = 0$
$\frac{5x + 15}{x + 3} = 0$
$\frac{5(x + 3)}{x + 3} = 0$
5 ≠ 0
Ответ: нет корней
$\frac{2}{x - 1} + \frac{1}{x + 1} = 0$
$\frac{2(x + 1) + x - 1}{(x - 1)(x + 1)} = 0$
$\frac{2x + 2 + x - 1}{x^2 - 1} = 0$
$\frac{3x + 1}{x^2 - 1} = 0$
$\begin{equation*}
\begin{cases}
3x + 1 = 0 &\\
x^2 - 1 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
3x = -1 &\\
x^2 ≠ 1 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = -\frac{1}{3} &\\
x ≠ ±1 &
\end{cases}
\end{equation*}$
Ответ: $x = -\frac{1}{3}$
$\frac{3}{x - 2} = \frac{4}{x + 3}$
$\frac{3}{x - 2} - \frac{4}{x + 3} = 0$
$\frac{3(x + 3) - 4(x - 2)}{(x - 2)(x + 3)} = 0$
$\frac{3x + 9 - 4x + 8}{(x - 2)(x + 3)} = 0$
$\frac{17 - x}{(x - 2)(x + 3)} = 0$
$\begin{equation*}
\begin{cases}
x - 2 ≠ 0 &\\
x + 3 ≠ 0 &\\
17 - x = 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x ≠ 2 &\\
x ≠ -3 &\\
x = 17 &
\end{cases}
\end{equation*}$
Ответ: x = 17
$\frac{x}{x - 6} = 2$
$\frac{x}{x - 6} - 2 = 0$
$\frac{x - 2(x - 6)}{x - 6} = 0$
$\frac{x - 2x + 12}{x - 6} = 0$
$\frac{12 - x}{x - 6} = 0$
$\begin{equation*}
\begin{cases}
12 - x = 0 &\\
x - 6 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 12 &\\
x ≠ 6 &
\end{cases}
\end{equation*}$
Ответ: x = 12
$\frac{x - 4}{x - 3} = \frac{2x + 1}{2x - 1}$
$\frac{x - 4}{x - 3} - \frac{2x + 1}{2x - 1} = 0$
$\frac{(x - 4)(2x - 1) - (2x + 1)(x - 3)}{(x - 3)(2x - 1)} = 0$
$\frac{2x^2 - 8x - x + 4 - (2x^2 + x - 6x - 3)}{(x - 3)(2x - 1)} = 0$
$\frac{2x^2 - 9x + 4 - (2x^2 - 5x - 3)}{(x - 3)(2x - 1)} = 0$
$\frac{2x^2 - 9x + 4 - 2x^2 + 5x + 3}{(x - 3)(2x - 1)} = 0$
$\frac{7 - 4x}{(x - 3)(2x - 1)} = 0$
$\begin{equation*}
\begin{cases}
x - 3 ≠ 0 &\\
2x - 1 ≠ 0 &\\
7 - 4x = 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x ≠ 3 &\\
2x ≠ 1 &\\
4x = 7 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x ≠ 3 &\\
x ≠ \frac{1}{2} &\\
x = \frac{7}{4} = 1\frac{3}{4} &
\end{cases}
\end{equation*}$
Ответ: $x = 1\frac{3}{4}$
$\frac{x + 8}{x} - \frac{6}{x - 2} = 0$
$\frac{(x + 8)(x - 2) - 6x}{x(x - 2)} = 0$
$\frac{x^2 + 8x - 2x - 16 - 6x}{x(x - 2)} = 0$
$\frac{x^2 - 16}{x(x - 2)} = 0$
$\begin{equation*}
\begin{cases}
x ≠ 0 &\\
x - 2 ≠ 0 &\\
x^2 - 16 = 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x ≠ 0 &\\
x ≠ 2 &\\
x^2 = 16 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x ≠ 0 &\\
x ≠ 2 &\\
x = ±4 &
\end{cases}
\end{equation*}$
Ответ: x = ±4
$\frac{2x}{x - 5} - \frac{x^2 + 15x}{x^2 - 25} = 0$
$\frac{2x}{x - 5} - \frac{x^2 + 15x}{(x - 5)(x + 5)} = 0$
$\frac{2x(x + 5) - (x^2 + 15x)}{(x - 5)(x + 5)} = 0$
$\frac{2x^2 + 10x - x^2 - 15x}{(x - 5)(x + 5)} = 0$
$\frac{x^2 - 5x}{(x - 5)(x + 5)} = 0$
$\frac{x(x - 5)}{(x - 5)(x + 5)} = 0$
$\frac{x}{x + 5} = 0$
$\begin{equation*}
\begin{cases}
x = 0 &\\
x + 5 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 0 &\\
x ≠ -5 &
\end{cases}
\end{equation*}$
Ответ: x = 0
$3 - \frac{2x^2 - 5x}{x^2 - 3x} = 0$
$\frac{3(x^2 - 3x) - (2x^2 - 5x)}{x^2 - 3x} = 0$
$\frac{3x^2 - 9x - 2x^2 + 5x}{x^2 - 3x} = 0$
$\frac{x^2 - 4x}{x^2 - 3x} = 0$
$\frac{x(x - 4)}{x(x - 3)} = 0$
$\frac{x - 4}{x - 3} = 0$
$\begin{equation*}
\begin{cases}
x - 4 = 0 &\\
x - 3 ≠ 0 &
\end{cases}
\end{equation*}$
$\begin{equation*}
\begin{cases}
x = 4 &\\
x ≠ 3 &
\end{cases}
\end{equation*}$
Ответ: x = 4
Пожауйста, оцените решение