Докажите тождество:
$\frac{1}{(a - b)(a - c)} - \frac{1}{(a - b)(b - c)} + \frac{1}{(c - a)(c - b)} = 0$
$\frac{1}{(a - b)(a - c)} - \frac{1}{(a - b)(b - c)} + \frac{1}{(c - a)(c - b)} = 0$
$\frac{1}{(a - b)(a - c)} - \frac{1}{(a - b)(b - c)} + \frac{1}{(a - c)(b - c)} = 0$
$\frac{b - c - (a - c) + a - b}{(a - b)(a - c)(b - c)} = 0$
$\frac{b - c - a + c + a - b}{(a - b)(a - c)(b - c)} = 0$
$\frac{0}{(a - b)(a - c)(b - c)} = 0$
0 = 0
Пожауйста, оцените решение
