Решите уравнение:
а) $2x^2 - (2x^2 - 5x) - (4x - 2) = 5$;
б) $(y^3 + y) + (3 - 6y) - (4 - 5y) = -2$;
в) $(x^2 - 7x - 11) - (5x^2 - 13x - 18) = 16 - 4x^2$;
г) $(y^2 - 5y^5 - 19) - (5y^2 - 6y^5 - 9) = 22 - 4y^2$.
$2x^2 - (2x^2 - 5x) - (4x - 2) = 5$
$2x^2 - 2x^2 + 5x - 4x + 2 = 5$
x = 5 − 2
x = 3
$(y^3 + y) + (3 - 6y) - (4 - 5y) = -2$
$y^3 + y + 3 - 6y - 4 + 5y = -2$
$y^3 = -2 - 3 + 4$
$y^3 = -1$
y = −1
$(x^2 - 7x - 11) - (5x^2 - 13x - 18) = 16 - 4x^2$
$x^2 - 7x - 11 - 5x^2 + 13x + 18 + 4x^2 = 16$
6x = 16 + 11 − 18
6x = 9
x = 1,5
$(y^2 - 5y^5 - 19) - (5y^2 - 6y^5 - 9) = 22 - 4y^2$
$y^2 - 5y^5 - 19 - 5y^2 + 6y^5 + 9 + 4y^2 = 22$
$y^5 = 22 + 19 - 9$
$y^5 = 32$
y = 2
Пожауйста, оцените решение
